8x-3(4x-5)=2(7x+6)-9

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Solution for 8x-3(4x-5)=2(7x+6)-9 equation: 



8x-3(4x-5)=2(7x+6)-9

We move all terms to the left:

8x-3(4x-5)-(2(7x+6)-9)=0

We multiply parentheses

8x-12x-(2(7x+6)-9)+15=0



We calculate terms in parentheses: -(2(7x+6)-9), so:

2(7x+6)-9

We multiply parentheses

14x+12-9

We add all the numbers together, and all the variables

14x+3

Back to the equation:

-(14x+3)



We add all the numbers together, and all the variables

-4x-(14x+3)+15=0

We get rid of parentheses

-4x-14x-3+15=0

We add all the numbers together, and all the variables

-18x+12=0

We move all terms containing x to the left, all other terms to the right

-18x=-12

x=-12/-18

x=2/3

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