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8x-3(x+2)=2(x+3)
We move all terms to the left:
8x-3(x+2)-(2(x+3))=0
We multiply parentheses
8x-3x-(2(x+3))-6=0
We calculate terms in parentheses: -(2(x+3)), so:We add all the numbers together, and all the variables
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
5x-(2x+6)-6=0
We get rid of parentheses
5x-2x-6-6=0
We add all the numbers together, and all the variables
3x-12=0
We move all terms containing x to the left, all other terms to the right
3x=12
x=12/3
x=4
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