8x-3(x+4)=4(x-3)+1x

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Solution for 8x-3(x+4)=4(x-3)+1x equation:


Simplifying
8x + -3(x + 4) = 4(x + -3) + 1x

Reorder the terms:
8x + -3(4 + x) = 4(x + -3) + 1x
8x + (4 * -3 + x * -3) = 4(x + -3) + 1x
8x + (-12 + -3x) = 4(x + -3) + 1x

Reorder the terms:
-12 + 8x + -3x = 4(x + -3) + 1x

Combine like terms: 8x + -3x = 5x
-12 + 5x = 4(x + -3) + 1x

Reorder the terms:
-12 + 5x = 4(-3 + x) + 1x
-12 + 5x = (-3 * 4 + x * 4) + 1x
-12 + 5x = (-12 + 4x) + 1x

Combine like terms: 4x + 1x = 5x
-12 + 5x = -12 + 5x

Add '12' to each side of the equation.
-12 + 12 + 5x = -12 + 12 + 5x

Combine like terms: -12 + 12 = 0
0 + 5x = -12 + 12 + 5x
5x = -12 + 12 + 5x

Combine like terms: -12 + 12 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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