8x-3(x-1)=4(x-1)+5

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Solution for 8x-3(x-1)=4(x-1)+5 equation: 



8x-3(x-1)=4(x-1)+5

We move all terms to the left:

8x-3(x-1)-(4(x-1)+5)=0

We multiply parentheses

8x-3x-(4(x-1)+5)+3=0



We calculate terms in parentheses: -(4(x-1)+5), so:

4(x-1)+5

We multiply parentheses

4x-4+5

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

5x-(4x+1)+3=0

We get rid of parentheses

5x-4x-1+3=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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