8x-3(x-2)=3(x+4)

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Solution for 8x-3(x-2)=3(x+4) equation: 



8x-3(x-2)=3(x+4)

We move all terms to the left:

8x-3(x-2)-(3(x+4))=0

We multiply parentheses

8x-3x-(3(x+4))+6=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

5x-(3x+12)+6=0

We get rid of parentheses

5x-3x-12+6=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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