8x-3+(7x-(3(x+5)+7))+7))=7(x+8

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Solution for 8x-3+(7x-(3(x+5)+7))+7))=7(x+8 equation: 



8x-3+(7x-(3(x+5)+7))+7))=7(x+8

We move all terms to the left:

8x-3+(7x-(3(x+5)+7))+7))-(7(x+8)=0

We add all the numbers together, and all the variables

8x+(7x-(3(x+5)+7))+7))-(7(x+5)=0

We add all the numbers together, and all the variables

8x+(7x-(3(x+5)+7))+7))-(7(x=0



We calculate terms in parentheses: +(7x-(3(x+5)+7)), so:

7x-(3(x+5)+7)



We calculate terms in parentheses: -(3(x+5)+7), so:

3(x+5)+7

We multiply parentheses

3x+15+7

We add all the numbers together, and all the variables

3x+22

Back to the equation:

-(3x+22)



We get rid of parentheses

7x-3x-22

We add all the numbers together, and all the variables

4x-22

Back to the equation:

+(4x-22)



We get rid of parentheses

8x+4x+7))-(7(x-22=0

We add all the numbers together, and all the variables

12x+7))-(7(x-22=0

We move all terms containing x to the left, all other terms to the right

12x+7))-(7(x=22

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