8x-3+4x=4(x-2)-3

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Solution for 8x-3+4x=4(x-2)-3 equation: 



8x-3+4x=4(x-2)-3

We move all terms to the left:

8x-3+4x-(4(x-2)-3)=0

We add all the numbers together, and all the variables

12x-(4(x-2)-3)-3=0



We calculate terms in parentheses: -(4(x-2)-3), so:

4(x-2)-3

We multiply parentheses

4x-8-3

We add all the numbers together, and all the variables

4x-11

Back to the equation:

-(4x-11)



We get rid of parentheses

12x-4x+11-3=0

We add all the numbers together, and all the variables

8x+8=0

We move all terms containing x to the left, all other terms to the right

8x=-8

x=-8/8

x=-1

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