8x-3+x=4(x-3)-6

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Solution for 8x-3+x=4(x-3)-6 equation: 



8x-3+x=4(x-3)-6

We move all terms to the left:

8x-3+x-(4(x-3)-6)=0

We add all the numbers together, and all the variables

9x-(4(x-3)-6)-3=0



We calculate terms in parentheses: -(4(x-3)-6), so:

4(x-3)-6

We multiply parentheses

4x-12-6

We add all the numbers together, and all the variables

4x-18

Back to the equation:

-(4x-18)



We get rid of parentheses

9x-4x+18-3=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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