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8x-3/3x=12
We move all terms to the left:
8x-3/3x-(12)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
8x*3x-12*3x-3=0
Wy multiply elements
24x^2-36x-3=0
a = 24; b = -36; c = -3;
Δ = b2-4ac
Δ = -362-4·24·(-3)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12\sqrt{11}}{2*24}=\frac{36-12\sqrt{11}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12\sqrt{11}}{2*24}=\frac{36+12\sqrt{11}}{48} $
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