8x-3/5x=7

Solution for 8x-3/5x=7 equation:

8x-3/5x=7

We move all terms to the left:

8x-3/5x-(7)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We multiply all the terms by the denominator


8x*5x-7*5x-3=0

Wy multiply elements

40x^2-35x-3=0

a = 40; b = -35; c = -3;
Δ = b2-4ac
Δ = -352-4·40·(-3)
Δ = 1705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1705}}{2*40}=\frac{35-\sqrt{1705}}{80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1705}}{2*40}=\frac{35+\sqrt{1705}}{80}
$