8x-3/x=2

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Solution for 8x-3/x=2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

8*x-(3/x) = 2 // - 2

8*x-(3/x)-2 = 0

8*x-3*x^-1-2 = 0

8*x^1-3*x^-1-2*x^0 = 0

(8*x^2-2*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(8*x^2-2*x^1-3*x^0) = 0

x^1

8*x^2-2*x-3 = 0

8*x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*4*8)

DELTA = 100

DELTA > 0

x = (100^(1/2)+2)/(2*8) or x = (2-100^(1/2))/(2*8)

x = 3/4 or x = -1/2

x in { -1/2, 3/4} 

x in { -1/2, 3/4 }

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