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8x-3/x=3
We move all terms to the left:
8x-3/x-(3)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
8x*x-3*x-3=0
We add all the numbers together, and all the variables
-3x+8x*x-3=0
Wy multiply elements
8x^2-3x-3=0
a = 8; b = -3; c = -3;
Δ = b2-4ac
Δ = -32-4·8·(-3)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{105}}{2*8}=\frac{3-\sqrt{105}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{105}}{2*8}=\frac{3+\sqrt{105}}{16} $
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