8x-36=x(x-4)

Solution for 8x-36=x(x-4) equation:

8x-36=x(x-4)

We move all terms to the left:

8x-36-(x(x-4))=0


We calculate terms in parentheses: -(x(x-4)), so:

x(x-4)

We multiply parentheses

x^2-4x

Back to the equation:

-(x^2-4x)


We get rid of parentheses

-x^2+8x+4x-36=0

We add all the numbers together, and all the variables

-1x^2+12x-36=0

a = -1; b = 12; c = -36;
Δ = b2-4ac
Δ = 122-4·(-1)·(-36)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{-2}=+6$