8x-3=3(x-4)+19

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Solution for 8x-3=3(x-4)+19 equation: 



8x-3=3(x-4)+19

We move all terms to the left:

8x-3-(3(x-4)+19)=0



We calculate terms in parentheses: -(3(x-4)+19), so:

3(x-4)+19

We multiply parentheses

3x-12+19

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We get rid of parentheses

8x-3x-7-3=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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