8x-3=8(x+2)x=

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Solution for 8x-3=8(x+2)x= equation: 



8x-3=8(x+2)x=

We move all terms to the left:

8x-3-(8(x+2)x)=0



We calculate terms in parentheses: -(8(x+2)x), so:

8(x+2)x

We multiply parentheses

8x^2+16x

Back to the equation:

-(8x^2+16x)



We get rid of parentheses

-8x^2+8x-16x-3=0

We add all the numbers together, and all the variables

-8x^2-8x-3=0

a = -8; b = -8; c = -3;
Δ = b2-4ac
Δ = -82-4·(-8)·(-3)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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