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8x-3x=x-4(2+2x)
We move all terms to the left:
8x-3x-(x-4(2+2x))=0
We add all the numbers together, and all the variables
8x-3x-(x-4(2x+2))=0
We add all the numbers together, and all the variables
5x-(x-4(2x+2))=0
We calculate terms in parentheses: -(x-4(2x+2)), so:We get rid of parentheses
x-4(2x+2)
We multiply parentheses
x-8x-8
We add all the numbers together, and all the variables
-7x-8
Back to the equation:
-(-7x-8)
5x+7x+8=0
We add all the numbers together, and all the variables
12x+8=0
We move all terms containing x to the left, all other terms to the right
12x=-8
x=-8/12
x=-2/3
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