8x-4(8-x)=64

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Solution for 8x-4(8-x)=64 equation: 



8x-4(8-x)=64

We move all terms to the left:

8x-4(8-x)-(64)=0

We add all the numbers together, and all the variables

8x-4(-1x+8)-64=0

We multiply parentheses

8x+4x-32-64=0

We add all the numbers together, and all the variables

12x-96=0

We move all terms containing x to the left, all other terms to the right

12x=96

x=96/12

x=8

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