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8x-4+5=3+2(x+1)
We move all terms to the left:
8x-4+5-(3+2(x+1))=0
We add all the numbers together, and all the variables
8x-(3+2(x+1))+1=0
We calculate terms in parentheses: -(3+2(x+1)), so:We get rid of parentheses
3+2(x+1)
determiningTheFunctionDomain 2(x+1)+3
We multiply parentheses
2x+2+3
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
8x-2x-5+1=0
We add all the numbers together, and all the variables
6x-4=0
We move all terms containing x to the left, all other terms to the right
6x=4
x=4/6
x=2/3
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