8x-4/4x=2

Solution for 8x-4/4x=2 equation:

8x-4/4x=2

We move all terms to the left:

8x-4/4x-(2)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We multiply all the terms by the denominator


8x*4x-2*4x-4=0

Wy multiply elements

32x^2-8x-4=0

a = 32; b = -8; c = -4;
Δ = b2-4ac
Δ = -82-4·32·(-4)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-24}{2*32}=\frac{-16}{64}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+24}{2*32}=\frac{32}{64}
=1/2
$