8x-40-2x+6=10-8x+12

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Solution for 8x-40-2x+6=10-8x+12 equation: 



8x-40-2x+6=10-8x+12

We move all terms to the left:

8x-40-2x+6-(10-8x+12)=0

We add all the numbers together, and all the variables

8x-2x-(-8x+22)-40+6=0

We add all the numbers together, and all the variables

6x-(-8x+22)-34=0

We get rid of parentheses

6x+8x-22-34=0

We add all the numbers together, and all the variables

14x-56=0

We move all terms containing x to the left, all other terms to the right

14x=56

x=56/14

x=4

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