8x-40=3(-x+5)

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Solution for 8x-40=3(-x+5) equation: 



8x-40=3(-x+5)

We move all terms to the left:

8x-40-(3(-x+5))=0

We add all the numbers together, and all the variables

8x-(3(-1x+5))-40=0



We calculate terms in parentheses: -(3(-1x+5)), so:

3(-1x+5)

We multiply parentheses

-3x+15

Back to the equation:

-(-3x+15)



We get rid of parentheses

8x+3x-15-40=0

We add all the numbers together, and all the variables

11x-55=0

We move all terms containing x to the left, all other terms to the right

11x=55

x=55/11

x=5

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