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8x-4=2(3x-2)+2x
We move all terms to the left:
8x-4-(2(3x-2)+2x)=0
We calculate terms in parentheses: -(2(3x-2)+2x), so:We get rid of parentheses
2(3x-2)+2x
We add all the numbers together, and all the variables
2x+2(3x-2)
We multiply parentheses
2x+6x-4
We add all the numbers together, and all the variables
8x-4
Back to the equation:
-(8x-4)
8x-8x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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