8x-4=2(4x+1)-6

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Solution for 8x-4=2(4x+1)-6 equation: 



8x-4=2(4x+1)-6

We move all terms to the left:

8x-4-(2(4x+1)-6)=0



We calculate terms in parentheses: -(2(4x+1)-6), so:

2(4x+1)-6

We multiply parentheses

8x+2-6

We add all the numbers together, and all the variables

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

8x-8x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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