8x-4=2(4x-4)8x-4=8x-8

Solution for 8x-4=2(4x-4)8x-4=8x-8 equation:

8x-4=2(4x-4)8x-4=8x-8

We move all terms to the left:

8x-4-(2(4x-4)8x-4)=0


We calculate terms in parentheses: -(2(4x-4)8x-4), so:

2(4x-4)8x-4

We multiply parentheses

64x^2-64x-4

Back to the equation:

-(64x^2-64x-4)


We get rid of parentheses

-64x^2+8x+64x+4-4=0

We add all the numbers together, and all the variables

-64x^2+72x=0

a = -64; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·(-64)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*-64}=\frac{-144}{-128}
=1+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*-64}=\frac{0}{-128}
=0
$