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8x-4=3(x+2)+4(2x-4)
We move all terms to the left:
8x-4-(3(x+2)+4(2x-4))=0
We calculate terms in parentheses: -(3(x+2)+4(2x-4)), so:We get rid of parentheses
3(x+2)+4(2x-4)
We multiply parentheses
3x+8x+6-16
We add all the numbers together, and all the variables
11x-10
Back to the equation:
-(11x-10)
8x-11x+10-4=0
We add all the numbers together, and all the variables
-3x+6=0
We move all terms containing x to the left, all other terms to the right
-3x=-6
x=-6/-3
x=+2
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