8x-4=3(x+3)-20

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Solution for 8x-4=3(x+3)-20 equation: 



8x-4=3(x+3)-20

We move all terms to the left:

8x-4-(3(x+3)-20)=0



We calculate terms in parentheses: -(3(x+3)-20), so:

3(x+3)-20

We multiply parentheses

3x+9-20

We add all the numbers together, and all the variables

3x-11

Back to the equation:

-(3x-11)



We get rid of parentheses

8x-3x+11-4=0

We add all the numbers together, and all the variables

5x+7=0

We move all terms containing x to the left, all other terms to the right

5x=-7

x=-7/5

x=-1+2/5

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