8x-4x-2+1x=3(x+2)

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Solution for 8x-4x-2+1x=3(x+2) equation: 



8x-4x-2+1x=3(x+2)

We move all terms to the left:

8x-4x-2+1x-(3(x+2))=0

We add all the numbers together, and all the variables

5x-(3(x+2))-2=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

5x-3x-6-2=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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