8x-5(4x+1)-1+2=(4x-3)

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Solution for 8x-5(4x+1)-1+2=(4x-3) equation: 



8x-5(4x+1)-1+2=(4x-3)

We move all terms to the left:

8x-5(4x+1)-1+2-((4x-3))=0

We add all the numbers together, and all the variables

8x-5(4x+1)-((4x-3))+1=0

We multiply parentheses

8x-20x-((4x-3))-5+1=0



We calculate terms in parentheses: -((4x-3)), so:

(4x-3)

We get rid of parentheses

4x-3

Back to the equation:

-(4x-3)



We add all the numbers together, and all the variables

-12x-(4x-3)-4=0

We get rid of parentheses

-12x-4x+3-4=0

We add all the numbers together, and all the variables

-16x-1=0

We move all terms containing x to the left, all other terms to the right

-16x=1

x=1/-16

x=-1/16

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