8x-5(4x+1)=-1-2(4x-3)

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Solution for 8x-5(4x+1)=-1-2(4x-3) equation: 



8x-5(4x+1)=-1-2(4x-3)

We move all terms to the left:

8x-5(4x+1)-(-1-2(4x-3))=0

We multiply parentheses

8x-20x-(-1-2(4x-3))-5=0



We calculate terms in parentheses: -(-1-2(4x-3)), so:

-1-2(4x-3)

determiningTheFunctionDomain
-2(4x-3)-1

We multiply parentheses

-8x+6-1

We add all the numbers together, and all the variables

-8x+5

Back to the equation:

-(-8x+5)



We add all the numbers together, and all the variables

-12x-(-8x+5)-5=0

We get rid of parentheses

-12x+8x-5-5=0

We add all the numbers together, and all the variables

-4x-10=0

We move all terms containing x to the left, all other terms to the right

-4x=10

x=10/-4

x=-2+1/2

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