8x-5(8-4x)=-40-2x

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Solution for 8x-5(8-4x)=-40-2x equation: 



8x-5(8-4x)=-40-2x

We move all terms to the left:

8x-5(8-4x)-(-40-2x)=0

We add all the numbers together, and all the variables

8x-5(-4x+8)-(-2x-40)=0

We multiply parentheses

8x+20x-(-2x-40)-40=0

We get rid of parentheses

8x+20x+2x+40-40=0

We add all the numbers together, and all the variables

30x=0

x=0/30

x=0

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