8x-5(x+3)=3(7x+1)

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Solution for 8x-5(x+3)=3(7x+1) equation: 



8x-5(x+3)=3(7x+1)

We move all terms to the left:

8x-5(x+3)-(3(7x+1))=0

We multiply parentheses

8x-5x-(3(7x+1))-15=0



We calculate terms in parentheses: -(3(7x+1)), so:

3(7x+1)

We multiply parentheses

21x+3

Back to the equation:

-(21x+3)



We add all the numbers together, and all the variables

3x-(21x+3)-15=0

We get rid of parentheses

3x-21x-3-15=0

We add all the numbers together, and all the variables

-18x-18=0

We move all terms containing x to the left, all other terms to the right

-18x=18

x=18/-18

x=-1

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