8x-5(x-2)=40-20(x-3)

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Solution for 8x-5(x-2)=40-20(x-3) equation: 



8x-5(x-2)=40-20(x-3)

We move all terms to the left:

8x-5(x-2)-(40-20(x-3))=0

We multiply parentheses

8x-5x-(40-20(x-3))+10=0



We calculate terms in parentheses: -(40-20(x-3)), so:

40-20(x-3)

determiningTheFunctionDomain
-20(x-3)+40

We multiply parentheses

-20x+60+40

We add all the numbers together, and all the variables

-20x+100

Back to the equation:

-(-20x+100)



We add all the numbers together, and all the variables

3x-(-20x+100)+10=0

We get rid of parentheses

3x+20x-100+10=0

We add all the numbers together, and all the variables

23x-90=0

We move all terms containing x to the left, all other terms to the right

23x=90

x=90/23

x=3+21/23

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