8x-5+6x+3(x-4)=10x-6x+11(x+4)

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Solution for 8x-5+6x+3(x-4)=10x-6x+11(x+4) equation: 



8x-5+6x+3(x-4)=10x-6x+11(x+4)

We move all terms to the left:

8x-5+6x+3(x-4)-(10x-6x+11(x+4))=0

We add all the numbers together, and all the variables

14x+3(x-4)-(10x-6x+11(x+4))-5=0

We multiply parentheses

14x+3x-(10x-6x+11(x+4))-12-5=0



We calculate terms in parentheses: -(10x-6x+11(x+4)), so:

10x-6x+11(x+4)

We add all the numbers together, and all the variables

4x+11(x+4)

We multiply parentheses

4x+11x+44

We add all the numbers together, and all the variables

15x+44

Back to the equation:

-(15x+44)



We add all the numbers together, and all the variables

17x-(15x+44)-17=0

We get rid of parentheses

17x-15x-44-17=0

We add all the numbers together, and all the variables

2x-61=0

We move all terms containing x to the left, all other terms to the right

2x=61

x=61/2

x=30+1/2

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