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8x-5/3x-5=3
We move all terms to the left:
8x-5/3x-5-(3)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
8x-5/3x-8=0
We multiply all the terms by the denominator
8x*3x-8*3x-5=0
Wy multiply elements
24x^2-24x-5=0
a = 24; b = -24; c = -5;
Δ = b2-4ac
Δ = -242-4·24·(-5)
Δ = 1056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1056}=\sqrt{16*66}=\sqrt{16}*\sqrt{66}=4\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{66}}{2*24}=\frac{24-4\sqrt{66}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{66}}{2*24}=\frac{24+4\sqrt{66}}{48} $
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