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8x-5=3(2x-3)+12
We move all terms to the left:
8x-5-(3(2x-3)+12)=0
We calculate terms in parentheses: -(3(2x-3)+12), so:We get rid of parentheses
3(2x-3)+12
We multiply parentheses
6x-9+12
We add all the numbers together, and all the variables
6x+3
Back to the equation:
-(6x+3)
8x-6x-3-5=0
We add all the numbers together, and all the variables
2x-8=0
We move all terms containing x to the left, all other terms to the right
2x=8
x=8/2
x=4
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