8x-5x(x-2x)=3x+10

Solution for 8x-5x(x-2x)=3x+10 equation:

8x-5x(x-2x)=3x+10

We move all terms to the left:

8x-5x(x-2x)-(3x+10)=0

We add all the numbers together, and all the variables

8x-5x(-1x)-(3x+10)=0

We multiply parentheses

5x^2+8x-(3x+10)=0

We get rid of parentheses

5x^2+8x-3x-10=0

We add all the numbers together, and all the variables

5x^2+5x-10=0

a = 5; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·5·(-10)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-15}{2*5}=\frac{-20}{10}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+15}{2*5}=\frac{10}{10}
=1
$