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8x-6=2x-4+2(5x-2)
We move all terms to the left:
8x-6-(2x-4+2(5x-2))=0
We calculate terms in parentheses: -(2x-4+2(5x-2)), so:We get rid of parentheses
2x-4+2(5x-2)
determiningTheFunctionDomain 2x+2(5x-2)-4
We multiply parentheses
2x+10x-4-4
We add all the numbers together, and all the variables
12x-8
Back to the equation:
-(12x-8)
8x-12x+8-6=0
We add all the numbers together, and all the variables
-4x+2=0
We move all terms containing x to the left, all other terms to the right
-4x=-2
x=-2/-4
x=1/2
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