8x-7+2x=4x+12-(x+30)

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Solution for 8x-7+2x=4x+12-(x+30) equation: 



8x-7+2x=4x+12-(x+30)

We move all terms to the left:

8x-7+2x-(4x+12-(x+30))=0

We add all the numbers together, and all the variables

10x-(4x+12-(x+30))-7=0



We calculate terms in parentheses: -(4x+12-(x+30)), so:

4x+12-(x+30)

determiningTheFunctionDomain
4x-(x+30)+12

We get rid of parentheses

4x-x-30+12

We add all the numbers together, and all the variables

3x-18

Back to the equation:

-(3x-18)



We get rid of parentheses

10x-3x+18-7=0

We add all the numbers together, and all the variables

7x+11=0

We move all terms containing x to the left, all other terms to the right

7x=-11

x=-11/7

x=-1+4/7

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