8x-7-6x+27=2(x+10)

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Solution for 8x-7-6x+27=2(x+10) equation:



8x-7-6x+27=2(x+10)
We move all terms to the left:
8x-7-6x+27-(2(x+10))=0
We add all the numbers together, and all the variables
2x-(2(x+10))+20=0
We calculate terms in parentheses: -(2(x+10)), so:
2(x+10)
We multiply parentheses
2x+20
Back to the equation:
-(2x+20)
We get rid of parentheses
2x-2x-20+20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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