8x-7-6x+27=2(x+10)

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Solution for 8x-7-6x+27=2(x+10) equation: 



8x-7-6x+27=2(x+10)

We move all terms to the left:

8x-7-6x+27-(2(x+10))=0

We add all the numbers together, and all the variables

2x-(2(x+10))+20=0



We calculate terms in parentheses: -(2(x+10)), so:

2(x+10)

We multiply parentheses

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

2x-2x-20+20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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