8x-8(3x+2)+10=8(4x-3)

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Solution for 8x-8(3x+2)+10=8(4x-3) equation: 



8x-8(3x+2)+10=8(4x-3)

We move all terms to the left:

8x-8(3x+2)+10-(8(4x-3))=0

We multiply parentheses

8x-24x-(8(4x-3))-16+10=0



We calculate terms in parentheses: -(8(4x-3)), so:

8(4x-3)

We multiply parentheses

32x-24

Back to the equation:

-(32x-24)



We add all the numbers together, and all the variables

-16x-(32x-24)-6=0

We get rid of parentheses

-16x-32x+24-6=0

We add all the numbers together, and all the variables

-48x+18=0

We move all terms containing x to the left, all other terms to the right

-48x=-18

x=-18/-48

x=3/8

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