8x-80-4(x+3)=9x-7-7x+1

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Solution for 8x-80-4(x+3)=9x-7-7x+1 equation:



8x-80-4(x+3)=9x-7-7x+1
We move all terms to the left:
8x-80-4(x+3)-(9x-7-7x+1)=0
We add all the numbers together, and all the variables
8x-4(x+3)-(2x-6)-80=0
We multiply parentheses
8x-4x-(2x-6)-12-80=0
We get rid of parentheses
8x-4x-2x+6-12-80=0
We add all the numbers together, and all the variables
2x-86=0
We move all terms containing x to the left, all other terms to the right
2x=86
x=86/2
x=43

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