8x-9(8-x)-1=10(9-x)+4(x-1)

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Solution for 8x-9(8-x)-1=10(9-x)+4(x-1) equation: 



8x-9(8-x)-1=10(9-x)+4(x-1)

We move all terms to the left:

8x-9(8-x)-1-(10(9-x)+4(x-1))=0

We add all the numbers together, and all the variables

8x-9(-1x+8)-(10(-1x+9)+4(x-1))-1=0

We multiply parentheses

8x+9x-(10(-1x+9)+4(x-1))-72-1=0



We calculate terms in parentheses: -(10(-1x+9)+4(x-1)), so:

10(-1x+9)+4(x-1)

We multiply parentheses

-10x+4x+90-4

We add all the numbers together, and all the variables

-6x+86

Back to the equation:

-(-6x+86)



We add all the numbers together, and all the variables

17x-(-6x+86)-73=0

We get rid of parentheses

17x+6x-86-73=0

We add all the numbers together, and all the variables

23x-159=0

We move all terms containing x to the left, all other terms to the right

23x=159

x=159/23

x=6+21/23

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