8x-x-3/2x=4

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Solution for 8x-x-3/2x=4 equation:



8x-x-3/2x=4
We move all terms to the left:
8x-x-3/2x-(4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
7x-3/2x-4=0
We multiply all the terms by the denominator
7x*2x-4*2x-3=0
Wy multiply elements
14x^2-8x-3=0
a = 14; b = -8; c = -3;
Δ = b2-4ac
Δ = -82-4·14·(-3)
Δ = 232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{232}=\sqrt{4*58}=\sqrt{4}*\sqrt{58}=2\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{58}}{2*14}=\frac{8-2\sqrt{58}}{28} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{58}}{2*14}=\frac{8+2\sqrt{58}}{28} $

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