8x/(x+1)=2-(8/(x+1))

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Solution for 8x/(x+1)=2-(8/(x+1)) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(8*x)/(x+1) = 2-(8/(x+1)) // - 2-(8/(x+1))

(8*x)/(x+1)+8/(x+1)-2 = 0

(8*x)/(x+1)+8/(x+1)+(-2*(x+1))/(x+1) = 0

8*x-2*(x+1)+8 = 0

8*x-2*x-2+8 = 0

6*x+6 = 0

(6*x+6)/(x+1) = 0

(6*x+6)/(x+1) = 0 // * x+1

6*x+6 = 0

6*x+6 = 0 // - 6

6*x = -6 // : 6

x = -6/6

x = -1

x in { -1} 

x belongs to the empty set

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