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8x/3+16=3x/2-12x=
We move all terms to the left:
8x/3+16-(3x/2-12x)=0
Domain of the equation: 2-12x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-12x)!=-2
x!=-2/1
x!=-2
x∈R
8x/3-(-12x+3x/2)+16=0
We get rid of parentheses
8x/3+12x-3x/2+16=0
We calculate fractions
There is no solution for this equation
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