8x/5x2=8

Solution for 8x/5x2=8 equation:

8x/5x^2=8

We move all terms to the left:

8x/5x^2-(8)=0


Domain of the equation: 5x^2!=0

x^2!=0/5

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


8x-8*5x^2=0

Wy multiply elements

-40x^2+8x=0

a = -40; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-40)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-40}=\frac{-16}{-80}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-40}=\frac{0}{-80}
=0
$