8x/x-4=6x+8/x-4

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Solution for 8x/x-4=6x+8/x-4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(8*x)/x-4 = 6*x+8/x-4 // - 6*x+8/x-4

(8*x)/x-(6*x)-(8/x)-4+4 = 0

(8*x)/x-6*x-8*x^-1-4+4 = 0

8*x^0-6*x^1-8*x^-1 = 0

(8*x^1-6*x^2-8*x^0)/(x^1) = 0 // * x^2

x^1*(8*x^1-6*x^2-8*x^0) = 0

x^1

8*x-6*x^2-8 = 0

8*x-6*x^2-8 = 0

DELTA = 8^2-(-8*(-6)*4)

DELTA = -128

DELTA < 0

x in { } 

x belongs to the empty set

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