8x2+108x+36=0

Solution for 8x2+108x+36=0 equation:

8x^2+108x+36=0

a = 8; b = 108; c = +36;
Δ = b2-4ac
Δ = 1082-4·8·36
Δ = 10512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10512}=\sqrt{144*73}=\sqrt{144}*\sqrt{73}=12\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-12\sqrt{73}}{2*8}=\frac{-108-12\sqrt{73}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+12\sqrt{73}}{2*8}=\frac{-108+12\sqrt{73}}{16}
$