8x2+10x+3=1/(4x2+7x+3)

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Solution for 8x2+10x+3=1/(4x2+7x+3) equation: 



8x^2+10x+3=1/(4x^2+7x+3)

We move all terms to the left:

8x^2+10x+3-(1/(4x^2+7x+3))=0



Domain of the equation: (4x^2+7x+3))!=0

x∈R



We multiply all the terms by the denominator


8x^2*(4x^2+7x+3))+10x*(4x^2+7x+3))-(1+3*(4x^2+7x+3))=0

We add all the numbers together, and all the variables

8x^2*(4x^2+7x+3))+10x*(4x^2+14x+3))-(1+3*(4x^2=0

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