8x2+13x+5=0

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Solution for 8x2+13x+5=0 equation: 



8x^2+13x+5=0

a = 8; b = 13; c = +5;
Δ = b2-4ac
Δ = 132-4·8·5
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-3}{2*8}=\frac{-16}{16}
=-1
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+3}{2*8}=\frac{-10}{16}
=-5/8
$

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